JS实现的字符串数组去重功能小结

本文实例讲述了JS实现的字符串数组去重功能。分享给大家供大家参考，具体如下：

这里只考虑最简单字符串的数组去重，暂不考虑，对象，函数，NaN等情况，这种用正则实现起来就吃力不讨好了。

非正则实现：ES6实现

<script>
let str_arr=["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr){
return [...new Set(arr)]
}
console.log(unique(str_arr))
</script>

运行结果：

ES5实现

<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
 function unique(arr) {
   return arr.filter(function(ele, index, array) {
     return array.indexOf(ele) === index
   })
 }
 console.log(unique(str_arr))
</script>

运行结果同上

ES3实现

<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr) {
 var obj = {},
   array = []
 for (var i = 0, len = arr.length; i < len; i++) {
   var key = arr[i] + typeof arr[i]
   if (!obj[key]) {
     obj[key] = true
     array.push(arr[i])
   }
 }
 return array
}
console.log(unique(str_arr))
</script>

运行结果同上

用正则实现

<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr) {
  return arr.sort().join(",,").
  replace(/(,|^)([^,]+)(,,\2)+(,|$)/g, "$1$2$4").
  replace(/,,+/g, ",").
  replace(/,$/, "").
  split(",")
}
console.log(unique(str_arr))
</script>

运行结果：

希望本文所述对大家JavaScript程序设计有所帮助。

来源：https://blog.csdn.net/longzhoufeng/article/details/72954403