网络编程
位置:首页>> 网络编程>> Python编程>> Python实现账号密码输错三次即锁定功能简单示例

Python实现账号密码输错三次即锁定功能简单示例

作者:Hubery_Fight  发布时间:2023-07-22 07:40:21 

标签:Python,账号密码,锁定

本文实例讲述了Python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下:

初学Python—1


#实现账号输错三次即锁定
user = "hubery"
passwd = "123"
confirm = 0
lock=0
fileOpen = open("username.txt","a+")
fileOpen.seek(0)
for i in range(3):
username = input("username:")
passsword = input("password:")
for line in fileOpen.readlines():
 if username == line.strip():
  print("账户已经锁定!")
  lock=1
  break
 else:
  continue
fileOpen.seek(0)
if user == username and lock ==0:
 if passwd == passsword:
  print("欢迎,欢迎!")
  confirm = 1
  break
 else:
  print("账号户或者密码错误!")
  continue
elif lock==1:
 continue
else:
 print("1账号或者密码错误!")
 continue
fileOpen.close()
if confirm == 0 and lock==0:
fileWrite=open("username.txt","a")
fileWrite.write(username+"\n")
fileWrite.close()

基本功能可以实现;

锁定的账号为第三次输错的用户名(待完善)

以下为完善版本,如有错误,请告知


import os
user = "hubery"
passwd = "123"
count = 0
lock = 0
fileOpen = open("username.txt", "a+")
fileOpen.seek(0)
while 1:
for i in range(5):
 username = input("username:")
 passsword = input("password:")
 for line in fileOpen.readlines():
  if username == line.strip():
   print("账户已经锁定!")
   lock = 1
   break
  else:
   continue
 fileOpen.seek(0)
 if user == username:
  if lock == 1:
   continue
  elif passsword == passwd:
   print("欢迎,欢迎!")
   os._exit(0)
  elif count < 2:
   print("账号或者密码错误!")
   count += 1
   continue
  else:
   fileOpen.write(username + "\n")
   fileOpen.flush()
   print("密码输入错误超过三次,账户已经锁定!")
   fileOpen.seek(0)
   continue
 else:
  print("账号密码错误!")
  continue
check=input("还想验证其他账户?(yes-继续,no-退出)")
if "no"==check.lower():
 os._exit(0)
else:
 continue
fileOpen.close()

希望本文所述对大家Python程序设计有所帮助。

来源:https://blog.csdn.net/sen1013293436/article/details/64545220

0
投稿

猜你喜欢

手机版 网络编程 asp之家 www.aspxhome.com