利用Python检测URL状态

需求：Python检测URL状态，并追加保存200的URL

代码一：

#! /usr/bin/env python
#coding=utf-8
import sys
import requests
def getHttpStatusCode(url):
 try:
   request = requests.get(url)
   httpStatusCode = request.status_code
   return httpStatusCode
 except requests.exceptions.HTTPError as e:
   return e

if __name__ == "__main__":
 with open('1.txt', 'r') as f:
   for line in f:
     try:
       status = getHttpStatusCode(line.strip('\n'))#换行符
       if status == 200:
         with open('200.txt','a') as f:
           f.write(line + '\n')
           print line
       else:
         print 'no 200 code'
     except Exception as e:
       print e

代码二：

#! /usr/bin/env python
# -*--coding:utf-8*-

import requests

def request_status(line):
 conn = requests.get(line)
 if conn.status_code == 200:
   with open('url_200.txt', 'a') as f:
     f.write(line + '\n')
   return line13   else:
   return None

if __name__ == '__main__':
 with open('/1.txt', 'rb') as f:
   for line in f:
     try:
       purge_url = request_status(line.strip('\n'))
     except Exception as e:
       pass

代码三：

#! /usr/bin/env python
#coding:utf-8
import os,urllib,linecache
import sys
result = list()

for x in linecache.updatecache(r'1.txt'):
 try:
   a = urllib.urlopen(x.replace('/n','')).getcode()
   #print x,a
 except Exception,e:
   print e
 if a == 200:
   #result.append(x)               #保存
   #result.sort()                    #排序结果
   #open('2.txt', 'w').write('％s' ％ '\n'.join(result)) #保存入结果文件
   with open ('200urllib.txt','a') as f: ## r只读，w可写，a追加
     f.write(x + '\n')
 else:
   print 'error'

总结

以上所述是小编给大家介绍的python 检测url 状态,网站的支持！
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来源：https://www.cnblogs.com/x00479/archive/2019/07/31/11275208.html