给Python的Django框架下搭建的BLOG添加RSS功能的教程

前些天有位网友建议我在博客中添加RSS订阅功能，觉得挺好，所以自己抽空看了一下如何在Django中添加RSS功能，发现使用Django中的syndication feed framework很容易实现。

    具体实现步骤和代码如下：

    1、Feed类

# -*- coding: utf-8 -*-
from django.conf import settings
from django.contrib.syndication.views import Feed
from django.utils.feedgenerator import Rss201rev2Feed

from blog.models import Article
from .constants import SYNC_STATUS

class ExtendedRSSFeed(Rss201rev2Feed):
mime_type = 'application/xml'
"""
Create a type of RSS feed that has content:encoded elements.
"""
def root_attributes(self):
 attrs = super(ExtendedRSSFeed, self).root_attributes()
 attrs['xmlns:content'] = 'http://purl.org/rss/1.0/modules/content/'
 return attrs

def add_item_elements(self, handler, item):
 super(ExtendedRSSFeed, self).add_item_elements(handler, item)
 handler.addQuickElement(u'content:encoded', item['content_encoded'])

class LatestArticleFeed(Feed):
feed_type = ExtendedRSSFeed

title = settings.WEBSITE_NAME
link = settings.WEBSITE_URL
author = settings.WEBSITE_NAME
description = settings.WEBSITE_DESC + u"关注python、django、vim、linux、web开发和互联网"

def items(self):
 return Article.objects.filter(hided=False, published=True, sync_status=SYNC_STATUS.SYNCED).order_by('-publish_date')[:10]

def item_extra_kwargs(self, item):
 return {'content_encoded': self.item_content_encoded(item)}

def item_title(self, item):
 return item.title

# item_link is only needed if NewsItem has no get_absolute_url method.
def item_link(self, item):
 return '/article/％s/' ％ item.slug

def item_description(self, item):
 return item.description

def item_author_name(self, item):
 return item.creator.get_full_name()

def item_pubdate(self, item):
 return item.publish_date

def item_content_encoded(self, item):
 return item.content

    2、URL配置

from django import VERSION

if VERSION[0: 2] > (1, 3):
from django.conf.urls import patterns, include, url
else:
from django.conf.urls.defaults import patterns, include, url
from .feeds import LatestArticleFeed

urlpatterns = patterns(
'',
url(r'^feed/$', LatestArticleFeed()),
)