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Java LinkedHashMap深入分析源码

作者:AllenC6  发布时间:2022-07-31 03:05:43 

标签:Java,LinkedHashMap

一、LinkedHashMap的类继承关系

Java LinkedHashMap深入分析源码

二、源码分析

1.自己对LinkedHashMap的理解

从继承关系上,我们看到LinkedHashMap继承了HashMap,它里面的增删改差遍历的逻辑都是使用的HashMap中的,但是LinkedHashMap比HashMap多了一个双向链,这个双向链是从第一个插入的元素开始按照插入顺序,连接起来,所以可以说LinkedHashMap是可以保证插入顺序的。

看图:这里就简单的给大家看一下这个链是啥样的,不画红黑树了

Java LinkedHashMap深入分析源码

2.如何做到双向链的增删改查

(1).增

1).是在创建新节点的时候,把双向链连接起来,注意有两种节点一个是TreeNode一个普通Node

源码:

Node<K,V> newNode(int hash, K key, V value, Node<K,V> e) {
       LinkedHashMap.Entry<K,V> p =
           new LinkedHashMap.Entry<K,V>(hash, key, value, e);
       linkNodeLast(p);
       return p;
   }
   TreeNode<K,V> newTreeNode(int hash, K key, V value, Node<K,V> next) {
       TreeNode<K,V> p = new TreeNode<K,V>(hash, key, value, next);
       linkNodeLast(p);
       return p;
   }
   private void linkNodeLast(LinkedHashMap.Entry<K,V> p) {
       LinkedHashMap.Entry<K,V> last = tail;
       tail = p;
       if (last == null)
           head = p;
       else {
           p.before = last;
           last.after = p;
       }
   }
   static class Entry<K,V> extends HashMap.Node<K,V> {
       Entry<K,V> before, after;
       Entry(int hash, K key, V value, Node<K,V> next) {
           super(hash, key, value, next);
       }
   }

代码太简单了,这里简单描述一下,就是添加新节点会创建Node,有两种Node:TreeNode和普通Node(注意这里多态的使用普通Node和LinedHashMap.Entry和TreeNode的关系看一下就明白了),在创建之后放到双向链最后面。

2).有好多人说了还有一个afterNodeInsertion方法,这个方法的名字就显示是在插入之后调用的,是不是在这个方法中也有修改链表的逻辑,我们来看这个方法

void afterNodeInsertion(boolean evict) { // possibly remove eldest
       LinkedHashMap.Entry<K,V> first;
       if (evict && (first = head) != null && removeEldestEntry(first)) {
           K key = first.key;
           removeNode(hash(key), key, null, false, true);
       }
   }
   protected boolean removeEldestEntry(Map.Entry<K,V> eldest) {
       return false;
   }

看这个判断,有一个永远是false,也就是说如果我们不重写这个removeEldestEntry方法,那这个afterNodeInsertion方法里的逻辑永远不会执行,那这个玩意儿是干啥的呢,看逻辑是用来移除最早的头节点的,不知道为啥写着么一段,默认不会执行!!!

(2).删

void afterNodeRemoval(Node<K,V> e) { // unlink
       LinkedHashMap.Entry<K,V> p =
               (LinkedHashMap.Entry<K,V>)e, b = p.before, a = p.after; // b是当前节点的前一个节点,a是后一个节点
       p.before = p.after = null; //先断开当前节点,把当前节点对上一个和下一个节点的引用置为空
       if (b == null) //当前节点的前一个节点是null,说明当前节点是头节点,那去掉当前节点之后,当前节点的后一个节点成为了链第一个,
           // 也就是头节点,当然有可能a也是null,那整个链就是空链,这种写法兼容了a也是null的情况
           head = a;
       else
           b.after = a; //如果当前节点不是头节点,直接去掉当前节点,当前节点的前一个和后一个连起来
       if (a == null) //如果当前节点的后一个节点是null,说明当前节点是尾节点,那把当前节点去掉后,当前节点的前一个节点成为了链的最后一个节点尾节点。
           tail = b;
       else
           a.before = b;//如果当前节点不是尾节点,直接去掉当前节点,当前节点的前一个和后一个连起来
   }

这个删除我们看一下在哪里调用的:

final Node<K,V> removeNode(int hash, Object key, Object value,
                              boolean matchValue, boolean movable) {
           ...
           if (node != null && (!matchValue || (v = node.value) == value ||
                                (value != null && value.equals(v)))) {
               if (node instanceof TreeNode)
                   ((TreeNode<K,V>)node).removeTreeNode(this, tab, movable);
               else if (node == p)
                   tab[index] = node.next;
               else
                   p.next = node.next;
               ++modCount;
               --size;
               afterNodeRemoval(node); //⭐️⭐️⭐️
               return node;
           }
       }
       return null;
   }

在HashMap的removeNode方法里,当时学习HashMap的时候还是有疑惑的这个方法干啥使的,还是一个没有方法体的空实现方法,现在明白了,就是在给子类重写呢,所以说LinkedHashMap增删改查基本上全是HashMap的逻辑。

(3).改

有几点要注意

1).首先声明一点afterNodeAccess这个方法虽然在HashMap中改变键值对value值的时候都会调用,但是它和改变值没啥关系,真正的改值的逻辑是HashMap中的例如putVal方法,这个方法只是在改完值之后调用一下

final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
                  boolean evict) {
           ...
           if (e != null) { // existing mapping for key
               V oldValue = e.value;
               if (!onlyIfAbsent || oldValue == null)
                   e.value = value;
               afterNodeAccess(e); //⭐️⭐️⭐️⭐️
               return oldValue;
           }
       }
       ++modCount;
       if (++size > threshold)
           resize();
       afterNodeInsertion(evict);
       return null;
   }

2).afterNodeAccess的真正作用是把刚刚访问过的节点放到双向链的末尾,一旦执行这个方法那就会打乱我们由插入顺序形成的链表,这个逻辑执不执行由accessOrder变量控制

/**
* 此方法的作用是将刚刚访问的节点e放到链表的尾端
*/
void afterNodeAccess(Node<K,V> e) {
   LinkedHashMap.Entry<K,V> last;
   // accessOrder = true 时 访问节点后才需要置于尾端
   // 如果e本身就在尾端,那就不需要操作
   if (accessOrder && (last = tail) != e) {
   // 记录节点e、e的前驱、e的后继
       LinkedHashMap.Entry<K,V> p = (LinkedHashMap.Entry<K,V>)e, b = p.before, a = p.after;
       // 第一步:现将p.after置空
       p.after = null;
       // 第二步:将e的前驱.after 连接上e的后继
       if (b == null)
       // b记录e的前驱,前驱为null,则e在表头,head置为e的后继
           head = a;
       else
       // 否则 e的前驱.after = e的后继
           b.after = a;
       // 第三步:将e的后继.before 连接上e的前驱
       if (a != null)
       // e的后继 != null,将e后继.before = e的前驱
           a.before = b;
       else
       // 否则e的后继 == null,即在e表尾(这里有点多余,前面已经判断在表尾不操作。。。)
           last = b;
       // 第四步:将节点e接入到链表的尾端
       if (last == null)
       // last == null,链表为空,head = p
           head = p;
       else {
       // p.before 指向last(链表尾端),尾端.after = p
           p.before = last;
           last.after = p;
       }
       // 第四步:更新链表新尾端tail
       tail = p;
       // 链表结构性调整,修改次数自增
       ++modCount;
   }
}

注意,到底会不会执行这个方法,是由accessOrder变量控制,而这个变量只有在构造方法中指定才会为ture,其他的构造方法默认都是false不执行这段逻辑:

public LinkedHashMap(int initialCapacity, float loadFactor) {
       super(initialCapacity, loadFactor);
       accessOrder = false;
   }
   /**
    * Constructs an empty insertion-ordered <tt>LinkedHashMap</tt> instance
    * with the specified initial capacity and a default load factor (0.75).
    *
    * @param  initialCapacity the initial capacity
    * @throws IllegalArgumentException if the initial capacity is negative
    */
   public LinkedHashMap(int initialCapacity) {
       super(initialCapacity);
       accessOrder = false;
   }
   /**
    * Constructs an empty insertion-ordered <tt>LinkedHashMap</tt> instance
    * with the default initial capacity (16) and load factor (0.75).
    */
   public LinkedHashMap() {
       super();
       accessOrder = false;
   }
   /**
    * Constructs an insertion-ordered <tt>LinkedHashMap</tt> instance with
    * the same mappings as the specified map.  The <tt>LinkedHashMap</tt>
    * instance is created with a default load factor (0.75) and an initial
    * capacity sufficient to hold the mappings in the specified map.
    *
    * @param  m the map whose mappings are to be placed in this map
    * @throws NullPointerException if the specified map is null
    */
   public LinkedHashMap(Map<? extends K, ? extends V> m) {
       super();
       accessOrder = false;
       putMapEntries(m, false);
   }
   /**
    * Constructs an empty <tt>LinkedHashMap</tt> instance with the
    * specified initial capacity, load factor and ordering mode.
    *
    * @param  initialCapacity the initial capacity
    * @param  loadFactor      the load factor
    * @param  accessOrder     the ordering mode - <tt>true</tt> for
    *         access-order, <tt>false</tt> for insertion-order
    * @throws IllegalArgumentException if the initial capacity is negative
    *         or the load factor is nonpositive
    */
   public LinkedHashMap(int initialCapacity,
                        float loadFactor,
                        boolean accessOrder) {
       super(initialCapacity, loadFactor);
       this.accessOrder = accessOrder;
   }

(4).查

public V get(Object key) {
       Node<K,V> e;
       if ((e = getNode(hash(key), key)) == null)
           return null;
       if (accessOrder)
           afterNodeAccess(e);
       return e.value;
   }
   /**
    * {@inheritDoc}
    */
   public V getOrDefault(Object key, V defaultValue) {
      Node<K,V> e;
      if ((e = getNode(hash(key), key)) == null)
          return defaultValue;
      if (accessOrder)
          afterNodeAccess(e);
      return e.value;
  }

没啥好说的,都是调用的HashMap的代码。

3.遍历

遍历 和hashMap一样,只不过重写了一些方法,重写是为了按插入顺序遍历

public Set<K> keySet() {
       Set<K> ks = keySet;
       if (ks == null) {
           ks = new LinkedKeySet();
           keySet = ks;
       }
       return ks;
   }
   final class LinkedKeySet extends AbstractSet<K> {
       public final int size()                 { return size; }
       public final void clear()               { LinkedHashMap.this.clear(); }
       public final Iterator<K> iterator() {
           return new LinkedKeyIterator();
       }
       public final boolean contains(Object o) { return containsKey(o); }
       public final boolean remove(Object key) {
           return removeNode(hash(key), key, null, false, true) != null;
       }
       public final Spliterator<K> spliterator()  {
           return Spliterators.spliterator(this, Spliterator.SIZED |
                                           Spliterator.ORDERED |
                                           Spliterator.DISTINCT);
       }
       public final void forEach(Consumer<? super K> action) {
           if (action == null)
               throw new NullPointerException();
           int mc = modCount;
           for (LinkedHashMap.Entry<K,V> e = head; e != null; e = e.after)
               action.accept(e.key);
           if (modCount != mc)
               throw new ConcurrentModificationException();
       }
   }
  public Collection<V> values() {
       Collection<V> vs = values;
       if (vs == null) {
           vs = new LinkedValues();
           values = vs;
       }
       return vs;
   }
   final class LinkedValues extends AbstractCollection<V> {
       public final int size()                 { return size; }
       public final void clear()               { LinkedHashMap.this.clear(); }
       public final Iterator<V> iterator() {
           return new LinkedValueIterator();
       }
       public final boolean contains(Object o) { return containsValue(o); }
       public final Spliterator<V> spliterator() {
           return Spliterators.spliterator(this, Spliterator.SIZED |
                                           Spliterator.ORDERED);
       }
       public final void forEach(Consumer<? super V> action) {
           if (action == null)
               throw new NullPointerException();
           int mc = modCount;
           for (LinkedHashMap.Entry<K,V> e = head; e != null; e = e.after)
               action.accept(e.value);
           if (modCount != mc)
               throw new ConcurrentModificationException();
       }
   }
   /**
    * Returns a {@link Set} view of the mappings contained in this map.
    * The set is backed by the map, so changes to the map are
    * reflected in the set, and vice-versa.  If the map is modified
    * while an iteration over the set is in progress (except through
    * the iterator's own <tt>remove</tt> operation, or through the
    * <tt>setValue</tt> operation on a map entry returned by the
    * iterator) the results of the iteration are undefined.  The set
    * supports element removal, which removes the corresponding
    * mapping from the map, via the <tt>Iterator.remove</tt>,
    * <tt>Set.remove</tt>, <tt>removeAll</tt>, <tt>retainAll</tt> and
    * <tt>clear</tt> operations.  It does not support the
    * <tt>add</tt> or <tt>addAll</tt> operations.
    * Its {@link Spliterator} typically provides faster sequential
    * performance but much poorer parallel performance than that of
    * {@code HashMap}.
    *
    * @return a set view of the mappings contained in this map
    */
   public Set<Map.Entry<K,V>> entrySet() {
       Set<Map.Entry<K,V>> es;
       return (es = entrySet) == null ? (entrySet = new LinkedEntrySet()) : es;
   }
   final class LinkedEntrySet extends AbstractSet<Map.Entry<K,V>> {
       public final int size()                 { return size; }
       public final void clear()               { LinkedHashMap.this.clear(); }
       public final Iterator<Map.Entry<K,V>> iterator() {
           return new LinkedEntryIterator();
       }
       public final boolean contains(Object o) {
           if (!(o instanceof Map.Entry))
               return false;
           Map.Entry<?,?> e = (Map.Entry<?,?>) o;
           Object key = e.getKey();
           Node<K,V> candidate = getNode(hash(key), key);
           return candidate != null && candidate.equals(e);
       }
       public final boolean remove(Object o) {
           if (o instanceof Map.Entry) {
               Map.Entry<?,?> e = (Map.Entry<?,?>) o;
               Object key = e.getKey();
               Object value = e.getValue();
               return removeNode(hash(key), key, value, true, true) != null;
           }
           return false;
       }
       public final Spliterator<Map.Entry<K,V>> spliterator() {
           return Spliterators.spliterator(this, Spliterator.SIZED |
                                           Spliterator.ORDERED |
                                           Spliterator.DISTINCT);
       }
       public final void forEach(Consumer<? super Map.Entry<K,V>> action) {
           if (action == null)
               throw new NullPointerException();
           int mc = modCount;
           for (LinkedHashMap.Entry<K,V> e = head; e != null; e = e.after)
               action.accept(e);
           if (modCount != mc)
               throw new ConcurrentModificationException();
       }
   }
   // Map overrides
   public void forEach(BiConsumer<? super K, ? super V> action) {
       if (action == null)
           throw new NullPointerException();
       int mc = modCount;
       for (LinkedHashMap.Entry<K,V> e = head; e != null; e = e.after)
           action.accept(e.key, e.value);
       if (modCount != mc)
           throw new ConcurrentModificationException();
   }
   public void replaceAll(BiFunction<? super K, ? super V, ? extends V> function) {
       if (function == null)
           throw new NullPointerException();
       int mc = modCount;
       for (LinkedHashMap.Entry<K,V> e = head; e != null; e = e.after)
           e.value = function.apply(e.key, e.value);
       if (modCount != mc)
           throw new ConcurrentModificationException();
   }

简单测试一下,是不是按顺序遍历:

public class LinkedHashMapTestMain {
   public static void main(String[] args) {
       LinkedHashMap<String,String> linkedHashMap = new LinkedHashMap<>();
       for (int i = 0; i < 100; i++) {
           linkedHashMap.put(i + "", i + "");
       }
       //第一种entrySet
       Set<Map.Entry<String, String>> entrySet = linkedHashMap.entrySet();
       Iterator<Map.Entry<String, String>> iterator = entrySet.iterator();
       while (iterator.hasNext()) {
           Map.Entry<String, String> entry = iterator.next();
           System.out.println("entrySet: " + "key: " + entry.getKey() + "--- value: " + entry.getValue());
       }
       for (Map.Entry<String, String> entry : entrySet){
           System.out.println("entrySet forEach循环: " + "key: " + entry.getKey() + "--- value: " + entry.getValue());
       }
       //第二种keySet
       Set<String> keySet = linkedHashMap.keySet();
       Iterator<String> keySetIterator = keySet.iterator();
       while (keySetIterator.hasNext()){
           String key = keySetIterator.next();
           System.out.println("keySet: " + "key: " + key + "--- value: " + linkedHashMap.get(key));
       }
       for (String key : keySet){
           System.out.println("keySet forEach循环: " + "key: " + key + "--- value: " + linkedHashMap.get(key));
       }
   }
}

执行结果:

entrySet: key: 0--- value: 0
entrySet: key: 1--- value: 1
entrySet: key: 2--- value: 2
entrySet: key: 3--- value: 3
entrySet: key: 4--- value: 4
entrySet: key: 5--- value: 5
entrySet: key: 6--- value: 6
entrySet: key: 7--- value: 7
entrySet: key: 8--- value: 8
entrySet: key: 9--- value: 9
entrySet: key: 10--- value: 10
entrySet: key: 11--- value: 11
entrySet: key: 12--- value: 12
entrySet: key: 13--- value: 13
entrySet: key: 14--- value: 14
entrySet: key: 15--- value: 15
entrySet: key: 16--- value: 16
entrySet: key: 17--- value: 17
entrySet: key: 18--- value: 18
entrySet: key: 19--- value: 19
entrySet: key: 20--- value: 20
entrySet: key: 21--- value: 21
entrySet: key: 22--- value: 22
entrySet: key: 23--- value: 23
entrySet: key: 24--- value: 24
entrySet: key: 25--- value: 25
entrySet: key: 26--- value: 26
entrySet: key: 27--- value: 27
entrySet: key: 28--- value: 28
entrySet: key: 29--- value: 29
entrySet: key: 30--- value: 30
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来源:https://blog.csdn.net/m0_37707561/article/details/125336796

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