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jsp页面中获取servlet请求中的参数的办法详解

作者:wdc  发布时间:2023-06-19 10:52:00 

标签:servlet,jsp页面传值

在JAVA WEB应用中,如何获取servlet请求中的参数,并传递给跳转的JSP页面?例如访问http://localhost:8088/bbs?id=1

当执行这个bbs servlet时,将url参数id的值传递给bbs.jsp页面?

1.首先要配置web.xml,见下面的配置:

<servlet>
<servlet-name>bbs</servlet-name>
<servlet-class>
 org.openjweb.core.servlet.BBSServlet
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>bbs</servlet-name>
<url-pattern>/bbs</url-pattern>
</servlet-mapping>

2.编写servlet类:

package org.openjweb.core.servlet;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class BBSServlet extends HttpServlet
{
private static final long serialVersionUID = 1L;
 public BBSServlet()
 {
   super();
   // TODO Auto-generated constructor stub
 }
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
//http://bbs.csdn.net/topics/90438353
  request.setCharacterEncoding("UTF-8");  //设置编码
  String id = request.getParameter("id");
  request.setAttribute("id", id);
  request.getRequestDispatcher("/bbs.jsp").forward(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
doGet(request, response);
}
}

在应用根目录创建bbs.jsp文件,内容为:

<%@ page contentType="text/html;charset=UTF-8"%>
<%
out.println(request.getAttribute("id"));
%>

注意很多人传递参数不成功是因为是在doGet方法中调用doPost,这里doGet方法不要调用doPost.

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