python编写扎金花小程序的实例代码

游戏规则：

一付扑克牌，去掉大小王，每个玩家发3张牌，最后比大小，看谁赢。

有以下几种牌：

豹子：三张一样的牌，如3张6.

顺金：又称同花顺，即3张同样花色的顺子， 如红桃 5、6、7

顺子：又称拖拉机，花色不同，但是顺子，如红桃5、方片6、黑桃7，组成的顺子

对子：2张牌一样

单张：单张最大的是A

这几种牌的大小顺序为， 豹子>顺金>顺子>对子>单张

程序需要实现的点：

1. 先生成一付完整的扑克牌

2. 给5个玩家随机发牌

3. 统一开牌，比大小，输出赢家是谁

主要思路：

 把各种牌用积分来计算，最后加上三张牌的基础积分。即：最终积分=基础积分+牌型积分。最后比较最红积分，谁的积分大，谁排名就靠前。 附上源码：

# -*- coding: utf-8 -*-
"""
# @Time   : 2021-01-07 14:55
# @author  : jianwei
# @Software : PyCharm
"""

import random
import operator

puke = [] # 存储扑克牌
num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
hua_list = ['梅花', '红桃', '黑桃', '方块']
sotr_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,
     '对子': 15, '顺子': 30, '顺金': 60, '豹子': 100}
count_new_list = [] # 存储玩家分数和排序后排名
count_dic = {} # 存储玩家分数
# 准备52张扑克
for hua in hua_list:
 for num in num_list:
   a = hua + num
   puke.append(a)
player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}
# 随机给五个玩家发牌
# print(len(puke))
for key, value in player_dic.items():
 for i in range(3):
   plate = random.sample(puke, 3)
   player_dic[key] = plate
   for i in plate:
     puke.remove(i)

# print(player_dic)

# 获取玩家的牌型
def paixing(list1):
 num = []
 huase = []
 for i in list1:
   a = i[2:]
   b = i[:2]
   num.append(a)
   huase.append(b)
 return num, huase

# 对数字的牌型进行排序
def sotr(num):
 new_num = []
 sort_list2 = []
 list1 = []
 for i in num:
   new_num.append(sotr_dic[i])
 new_num = sorted(new_num)
 for new in new_num:
   sort_list2.append([k for k, v in sotr_dic.items() if v == new])
 for m in sort_list2:
   for n in m:
     list1.append(n)
 return list1

# 对玩家的牌形统计分数
def count(num, huase):
 a = 0
 base_count = sotr_dic[num[0]] + sotr_dic[num[1]] + sotr_dic[num[2]]
 if num[0] == num[1] and num[1] == num[2]:
   paixing = '豹子'
   a = base_count + sotr_dic[paixing]
   # print(paixing, a)
 elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]] and sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and (huase[0] == huase[
   1] and huase[1] == huase[2]):
   paixing = '顺金'
   a = base_count + sotr_dic[paixing]
   # print(paixing, a)
 elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]]) and (sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and (
     huase[0] != huase[
   1] or huase[1] != huase[2]):
   paixing = '顺子'
   a = base_count + sotr_dic[paixing]
   # print(paixing, a)
 elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
     num[0] == num[2] and num[1] != num[0]):
   paixing = '对子'
   a = base_count + sotr_dic[paixing]
   # print(paixing, a)
 else:
   a = base_count
 return a

# 对存储玩家分数的字典进行排序
def compare(count_dic):
 d = list(zip(count_dic.values(), count_dic.keys()))
 return sorted(d, reverse=True)

for key, value in player_dic.items():
 # print(key,value)
 num, huase = paixing(value)
 # print(num,huase)
 num = sotr(num)
 # print(num, huase)
 count1 = count(num, huase)
 # print(count1)
 count_dic[key] = count1
 print(key + "的牌为：" + str(value))
 count_new_list = compare(count_dic)
# print(count_new_list)
print('最终排名：' + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][
 1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")

来源：https://blog.csdn.net/qq_48657881/article/details/112918817