基于Python计算圆周率pi代码实例

一 计算公式：

二 实现代码

（1）

import math
from tqdm import tqdm
import time
total,s,n,t=0.0,1,1.0,1.0
while(math.fabs(t)>=1e-6):
 total+=t
 n+=2
 s=-s
 t=s/n
k=total*4
print("π值是{:.10f} 运行时间为{:.4f}秒".format(k,time.clock()))
for i in tqdm(range(101)):
 print("\r{:3}％".format(i),end="")
 time.sleep(0.1)

（2）

import time
import math

class Index(object):
 def __init__(self, number=50, decimal=2):
   self.decimal = decimal
   self.number = number
   self.a = 100/number

def __call__(self, now, total):
   percentage = self.percentage_number(now, total)
   well_num = int(percentage / self.a)
   progress_bar_num = self.progress_bar(well_num)
   result = "\r％s ％s" ％ (progress_bar_num, percentage)
   return result

def percentage_number(self, now, total):
   return round(now / total * 100, self.decimal)

def progress_bar(self, num):
   well_num = "#" * num
   space_num = " " * (self.number - num)
   return '[％s％s]' ％ (well_num, space_num)
index = Index()
total,s,n,t=0.0,1,1.0,1.0
while(math.fabs(t)>=1e-6):
 total+=t
 n+=2
 s=-s
 t=s/n
k=total*4
start = 371
for i in range(start + 1):
 print(index(i, start), end='')
 time.sleep(0.01)
print("\n π值是{:.10f}".format(k))

(3)

import time
import math
total,s,n,t=0.0,1,1.0,1.0
while(math.fabs(t)>=1e-6):
 total+=t
 n+=2
 s=-s
 t=s/n
k=total*4
scale=50
print("".center(scale//2,"-"))
start = time.perf_counter()
for i in range(scale+1):
 a="*"*i
 b="."*(scale-i)
 c=(i/scale)*100
 d=time.perf_counter() - start
 print("\r{:^3.0f}％[{}->{}]{:.2f}s".format(c,a,b,d),end='')
 time.sleep(0.1)
print("\n π值是{:.10f}".format(k))

来源：https://www.cnblogs.com/linjiaxin59/p/12562697.html