python爬虫字体加密的解决

直接点 某8网 https://*****.b*b.h*****y*8*.com/

具体网址格式就是这样的但是为了安全起见,我就这样打码了.

抛出问题

我们看到这个号码是在页面上正常显示的

F12 又是这样就比较麻烦,不能直接获取.

用requests库也是获取不到正常想要的 源码的,因为字体加密了.

查看页面源代码又是这样的.所以就是我们想怎么解密呢.

解决步骤

• 获取到真正的源码

• 找到对应的字体库

• 进行解析操作.

获取到真正的源码

为什么用webdriver,因为requests拿不到真正的源码.

from selenium import webdriver
# --- 进行chrome的配置
options = webdriver.ChromeOptions()

prefs = {"profile.managed_default_content_settings.images": 2}  # 设置无图模式
options.add_experimental_option("prefs", prefs)
options.add_argument("service_args = ['–ignore-ssl-errors = true', '–ssl-protocol = TLSv1']")
options.binary_location = r'C:\Program Files\Google\Chrome\Application\chrome.exe'
# ---- chrome进行端口接管调用
options.add_argument('-incognito')

driver = webdriver.Chrome(options=options)
driver.set_page_load_timeout(5)
# --- 设置宽和高位置
driver.maximize_window()
# --- 拦截webdriver检测代码
driver.execute_cdp_cmd("Page.addScriptToEvaluateOnNewDocument",
                      {"source": """
                 Object.defineProperty(navigator, 'webdriver', {
                 get: () => undefined
                 })
                 """})

找到对应的字体库

这上面进行申明了告诉了我们这个是字体base64,然后就是那下来然后生成文件.

# 示例
import base64

# 省略了很长的...
b64_code = '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'

with open('font.ttf', 'wb') as f:
   f.write(base64.decodebytes(b64_code.encode()))

from fontTools.ttLib import TTFont  # 导包

font = TTFont('font.ttf')
font.saveXML('font.xml')

# 简单封装下
import base64
def w_tff(one_html):
   res_tff = re.findall(r';base64,(.*?)"', one_html, re.S)
   if res_tff and len(res_tff) == 1:
       new_res_ttf = res_tff[0]
       with open('123_new_ttf.ttf', 'wb') as f:
           f.write(base64.decodebytes(new_res_ttf.encode()))

读取文件找到里面的对应关系,就是 你这个数字的格式 是存储在.ttf文件里的.

from fontTools.ttLib import TTFont
def get_num_phone(es_str: str):
   # 加载字体生成映射关系
   path = '123_new_ttf.ttf'
   font = TTFont(path)

# font.saveXML('font.xml')   # 生成xml文件
   # 得到映射关系
   bestcmap = font.getBestCmap()

ss = {}
   for key, value in bestcmap.items():
       keys = hex(key).replace('0x', '').replace("&#x", "")  # 10进制转16进制
       if value == "zero":
           value = 0
       elif value == "one":
           value = 1
       elif value == "one":
           value = 1
       elif value == "two":
           value = 2
       elif value == "three":
           value = 3
       elif value == "four":
           value = 4
       elif value == "five":
           value = 5
       elif value == "six":
           value = 6
       elif value == "seven":
           value = 7
       elif value == "eight":
           value = 8
       elif value == "nine":
           value = 9
       elif value == "hyphen":
           value = "-"
       ss.update({
           keys: value
       })

need_re = es_str
   list_phone = ""
   try:
       for item in need_re.split(";"):
           if item:
               new_item = item.replace("&#x", "")
               list_phone += "".join(str(ss[new_item]))
       if not list_phone or len(list_phone) < 2:
           return None
       return list_phone
   except Exception as e:
       return None

<cmap>
   <tableVersion version="0"/>
   <cmap_format_4 platformID="0" platEncID="3" language="0">
     <map code="0x23" name="numbersign"/><!-- NUMBER SIGN -->
     <map code="0x2a" name="asterisk"/><!-- ASTERISK -->
     <map code="0x2b" name="plus"/><!-- PLUS SIGN -->
     <map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS -->
     <map code="0x2f" name="slash"/><!-- SOLIDUS -->
   </cmap_format_4>
   <cmap_format_0 platformID="1" platEncID="0" language="0">
     <map code="0x23" name="numbersign"/>
     <map code="0x2a" name="asterisk"/>
     <map code="0x2b" name="plus"/>
     <map code="0x2d" name="hyphen"/>
     <map code="0x2f" name="slash"/>
   </cmap_format_0>
   <cmap_format_4 platformID="3" platEncID="1" language="0">
     <map code="0x23" name="numbersign"/><!-- NUMBER SIGN -->
     <map code="0x2a" name="asterisk"/><!-- ASTERISK -->
     <map code="0x2b" name="plus"/><!-- PLUS SIGN -->
     <map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS -->
     <map code="0x2f" name="slash"/><!-- SOLIDUS -->
   </cmap_format_4>
   <cmap_format_12 platformID="3" platEncID="10" format="12" reserved="0" length="76" language="0" nGroups="5">
     <map code="0x23" name="numbersign"/><!-- NUMBER SIGN -->
     <map code="0x2a" name="asterisk"/><!-- ASTERISK -->
     <map code="0x2b" name="plus"/><!-- PLUS SIGN -->
     <map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS -->
     <map code="0x2f" name="slash"/><!-- SOLIDUS -->
     <map code="0x880fb" name="zero"/><!-- ???? -->
     <map code="0x880fc" name="one"/><!-- ???? -->
     <map code="0x880fd" name="two"/><!-- ???? -->
     <map code="0x880fe" name="three"/><!-- ???? -->
     <map code="0x880ff" name="four"/><!-- ???? -->
     <map code="0x88100" name="five"/><!-- ???? -->
     <map code="0x88101" name="six"/><!-- ???? -->
     <map code="0x88102" name="seven"/><!-- ???? -->
     <map code="0x88103" name="eight"/><!-- ???? -->
     <map code="0x88104" name="nine"/><!-- ???? -->
   </cmap_format_12>
 </cmap>

读取ttf文件,(再生成xml文件,第一次寻找映射关系是需要做的)

• font.getBestCmap() 获取映射关系表

• 我们观察 xml文件的cmap段进行研究 ,可以看到我们明确需要的结果

• keys = hex(key).replace('0x', '').replace("&#x", "") 10进制转16进制 ,会得到映射关系表 {'23': 'numbersign', '2a': 'asterisk', '2b': 'plus', '2d': '-', '2f': 'slash', '8826e': 0, '8826f': 1, '88270': 2, '88271': 3, '88272': 4, '88273': 5, '88274': 6, '88275': 7, '88276': 8, '88277': 9}

• 和从页面上那些来的结果 进行 逐个匹配调整就行了.

注意的点

webdriver拿下来的页面源码有可能有点问题,所以我用了 soup_text = bs4.BeautifulSoup(driver.page_source, 'lxml').text 的方法来处理源代码 (import bs4)

其他的就是一些小细节上的问题了.基本的思路就是这样的.

来源：https://blog.csdn.net/Ly_Word/article/details/129285363