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详解Java递归实现树形结构的两种方式

作者:一宿君  发布时间:2023-02-18 07:24:47 

标签:Java,递归,树形结构

0、引言

在开发的过程中,很多业务场景需要一个树形结构的结果集进行前端展示,也可以理解为是一个无限父子结构,常见的有报表指标结构、菜单结构等。Java中递归实现树形结构的两种常见方式如下:

  • Java7及以下纯Java递归实现

  • Java8及以上借助lamda表达式实现

1、数据准备

Java实体类NodePO对应数据库表

package com.wbs.pojo;

import lombok.Data;
import lombok.NoArgsConstructor;

import java.util.List;

@Data
@NoArgsConstructor
public class NodePO {

/**
    * 当前节点id
    */
   private String id;

/**
    * 当前节点名称
    */
   private String name;

/**
    * 父级节点id
    */
   private String parentId;

/**
    * 当前节点序号
    */
   private String orderNo;

/**
    * 子集节点
    */
   private List<NodePO> children;

/**
    * 构造函数
    * @param id
    * @param name
    * @param parentId
    * @param orderNo
    */
   public NodePO(String id,String name,String parentId,String orderNo){
       this.id = id;
       this.name = name;
       this.parentId = parentId;
       this.orderNo = orderNo;
   }
}

自己造一些数据模拟从数据库中查询出来的数据:

static final List<NodePO> nodePOs = Arrays.asList(
           new NodePO("1","一级节点1",null,"_0001"),
           new NodePO("2","二级节点1.1","1","_0002"),
           new NodePO("3","二级节点1.2","1","_0003"),

new NodePO("4","一级节点2",null,"_0004"),
           new NodePO("5","二级节点2.1","4","_0005"),
           new NodePO("6","二级节点2.2","4","_0006"),
           new NodePO("7"," * 节点2.2.1","6","_0007"),

new NodePO("8","一级节点3",null,"_0008"),
           new NodePO("9","二级节点3.1","8","_0009"),
           new NodePO("10"," * 节点3.1.1","9","_0010"),
           new NodePO("11","四级节点3.1.1.1","10","_0011"),
           new NodePO("12","五级节点3.1.1.1.1","11","_0012")
   );

2、类型转化

从开发的过程中发现直接操作实体类集合,专门指定某一个实体类封装的方法是不具有普适性的,所以将实体类集合统一转化为Map集合,操作方便,具有一定的普适性:

List<Map<String, Object>> mapList = BeanMapUtils.listBeanToListMap(jsonObject);

BeanMapUtils自己简单封装一个工具类(不惧普适性勿喷):

package com.wbs.util;

import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.JSONObject;
import com.google.common.collect.Lists;
import com.google.common.collect.Maps;
import lombok.SneakyThrows;
import org.springframework.cglib.beans.BeanMap;

import java.util.*;
import java.util.function.Function;
import java.util.stream.Collectors;

/**
* @author 一宿君
* @version Id: BeanMapUtils.java, v 0.1 Administrator Exp $$
* @date 2022-10-13 14:24:20
* @desc java实体类和map相互转换工具类
*/
public class BeanMapUtils {

/**
    * 将实体类对象属性转化为map对象
    * @param t
    * @param <T>
    * @return
    */
   public static <T> Map<String, Object> beanToMap(T t) {
       Map<String, Object> map = new HashMap<>();
       if (t != null) {
           if (t instanceof JSONObject){
               return (JSONObject)t;
           }
           BeanMap beanMap = BeanMap.create(t);
           for (Object key : beanMap.keySet()) {
               map.put(key.toString(), beanMap.get(key));
           }
       }
       return map;
   }

/**
    * 将map对象中转化为实体类对象
    * @param map
    * @param clazz
    * @param <T>
    * @return
    * @throws Exception
    */
   public static <T> T mapToBean(Map<String, Object> map,Class<T> clazz) throws Exception {
       T bean = clazz.newInstance();
       if (bean instanceof JSONObject){
           JSONObject jsonObject = (JSONObject)bean;
           Set<Map.Entry<String, Object>> entries = map.entrySet();
           for (Map.Entry<String, Object> entry : entries) {
               jsonObject.put(entry.getKey(),entry.getValue());
           }
           return (T)jsonObject;
       }
       BeanMap beanMap = BeanMap.create(bean);
       beanMap.putAll(map);
       return bean;
   }

/**
    * 通过lambda表达式将List<JavaBean>转化为List<Map<String, Object>>
    * @param objList
    * @param <T>
    * @return
    */
   public static <T> List<Map<String, Object>> listBeanToListMap(List<T> objList) {
       return objList.stream().map(new Function<T, Map<String, Object>>() {
           @Override
           public Map<String, Object> apply(T t) {
               Map<String,Object> map = Maps.newHashMap();
               if (t instanceof JSONObject){
                   return (JSONObject)t;
               }
               BeanMap beanMap = BeanMap.create(t);
               for (Object key : beanMap.keySet()) {
                   map.put(key.toString(), beanMap.get(key));
               }
               return map;
           }
       }).collect(Collectors.toList());
   }

/**
    * 通过lambda表达式将List<Map<String, Object>>转化为List<JavaBean>
    * @param mapList
    * @param <T>
    * @return
    */
   public static <T> List<T> listMapToListBean(List<Map<String,Object>> mapList,Class<T> clazz) {
       return mapList.stream().map(new Function<Map<String, Object>,T>() {
           @SneakyThrows
           @Override
           public T apply(Map<String, Object> map) {
               T t = clazz.newInstance();
               if (t instanceof JSONObject){
                   return (T)map;
               }
               BeanMap beanMap = BeanMap.create(t);
               beanMap.putAll(map);
               return t;
           }
       }).collect(Collectors.toList());
   }
}

其中org.springframework.cglib.beans.BeanMap;org.springframework:spring-core依赖下的工具包,spring-core核心依赖只要导入spring-boot-starter依赖即可

<dependency>
   <groupId>org.springframework.boot</groupId>
   <artifactId>spring-boot-starter</artifactId>
   <version>2.2.0.RELEASE</version>
</dependency>

详解Java递归实现树形结构的两种方式

3、递归实现方法

3.1、Java7及以下纯Java递归实现

既然是Java7及以下实现方式,那排序也用最原始的冒泡排序:

/**
    * 冒泡排序,小的在前,大的在后
    * @param list
    * @return
    */
   public static List<Map<String, Object>> sortJava7Map(List<Map<String, Object>> list){
       if(CollectionUtils.isEmpty(list)){
           return Lists.newArrayList();
       }
       boolean flag;
       int size = list.size();
       for (int i = 0; i < size - 1; i++) {
           flag = false;
           for (int j = 1; j < size - i; j++) {
               Map<String, Object> frontMap = list.get(j - 1);
               Map<String, Object> afterMap = list.get(j);
               if (String.valueOf(frontMap.get("orderNo")).compareTo(String.valueOf(afterMap.get("orderNo"))) > 0){
                   list.set(j - 1,afterMap);
                   list.set(j,frontMap);
                   flag = true;
               }
           }
           //如果没有发生位置互换,则退出循环
           if (!flag){
               break;
           }
       }
       return list;
   }

给定一个节点,获取它的所有子节点:

/**
    * Java7及以下版本获取子节点的方式
    * @param parentNode
    * @param allList
    * @return
    */
   public static List<Map<String, Object>> getJava7Children(Map<String,Object> parentNode,List<Map<String, Object>> allList){

//存放当前节点的直系子节点
       List<Map<String, Object>> curNodeChildrenList = Lists.newArrayList();

//存放直系子节点以外的节点
       List<Map<String, Object>> otherNodeList = Lists.newArrayList();

Object pId = parentNode.get("id");
       for (Map<String, Object> map : allList) {
           Object curPId = map.get("parentId");
           if (ObjectUtils.isNotEmpty(curPId) && Objects.equals(pId,curPId)){
               curNodeChildrenList.add(map);
           }else {
               otherNodeList.add(map);
           }
       }
       if (curNodeChildrenList.isEmpty()){
           return curNodeChildrenList;
       }
       //每一层级都进行排序
       curNodeChildrenList = sortJava7Map(curNodeChildrenList);

//迭代直系子节点再获取子节点
       for (Map<String, Object> map : curNodeChildrenList) {
           map.put("children",getJava7Children(map,otherNodeList));
       }
       return curNodeChildrenList;
   }

给出一个结果集,构建树形结果集:

/**
    * 使用Java7的方式获取树形结构
    * @param allList
    * @return
    */
   public static List<Map<String, Object>> getJava7ResultTree(List<Map<String, Object>> allList){
       //存放所有的一级节点
       List<Map<String, Object>> oneLevelNodeList = Lists.newArrayList();

for (Map<String, Object> map : allList) {
           if (ObjectUtils.isEmpty(map.get("parentId"))){
               map.put("children",getJava7Children(map,allList));
               oneLevelNodeList.add(map);
           }
       }
       return sortJava8Map(oneLevelNodeList);
   }

获取树形结构:

//转化为Map集合
List<Map<String, Object>> mapList = BeanMapUtils.listBeanToListMap(nodePOs);
//获取树形结构
List<Map<String, Object>> java7ResultTree = getJava7ResultTree(mapList);
//打印输出
System.out.println(JSON.toJSONString(java7ResultTree));

打印结果:

[{"orderNo":"_0001","children":[{"orderNo":"_0002","children":[],"name":"二级节点1.1","id":"2","parentId":"1"},{"orderNo":"_0003","children":[],"name":"二级节点1.2","id":"3","parentId":"1"}],"name":"一级节点1","id":"1"},{"orderNo":"_0004","children":[{"orderNo":"_0005","children":[],"name":"二级节点2.1","id":"5","parentId":"4"},{"orderNo":"_0006","children":[{"orderNo":"_0007","children":[],"name":" * 节点2.2.1","id":"7","parentId":"6"}],"name":"二级节点2.2","id":"6","parentId":"4"}],"name":"一级节点2","id":"4"},{"orderNo":"_0008","children":[{"orderNo":"_0009","children":[{"orderNo":"_0010","children":[{"orderNo":"_0011","children":[{"orderNo":"_0012","children":[],"name":"五级节点3.1.1.1.1","id":"12","parentId":"11"}],"name":"四级节点3.1.1.1","id":"11","parentId":"10"}],"name":" * 节点3.1.1","id":"10","parentId":"9"}],"name":"二级节点3.1","id":"9","parentId":"8"}],"name":"一级节点3","id":"8"}]

树形结构搞定!

3.2、Java8及以上借助lamda表达式实现

Java7的方式虽然实现了树形结构,但是有一定的缺点,比如:代码量比较大,逻辑相对较复杂,那Java8是如何简化,如下所示:

既然Java8有lamda表达式,那代码我们能省就省,先看排序,一行代码搞定:

/**
    * 根据orderNo排序树形结构的每一个层级
    * @param list
    * @return
    */
   public static List<Map<String, Object>> sortJava8Map(List<Map<String, Object>> list){
       if(CollectionUtils.isEmpty(list)){
           return Lists.newArrayList();
       }
       //关键之处,一行代码搞定
       list.sort(Comparator.comparing(m -> String.valueOf(m.get("orderNo"))));
       return list;
   }

给定一个节点,获取它的所有子节点:

释义:
filter: 过滤,相当于for循环,再if条件判断。
peek: 给定一个节点,往它的children塞子节点。

/**
    * 根据父级节点获取所有的子集节点
    * @param parentNode
    * @param allList
    * @return
    */
   public static List<Map<String, Object>> getJava8Children(Map<String,Object> parentNode, List<Map<String, Object>> allList){
       return allList.stream()
               .filter(curNode -> ObjectUtils.isNotEmpty(curNode.get("parentId")) && Objects.equals(curNode.get("parentId"),parentNode.get("id")))
               .peek(m -> m.put("children", getJava8Children(m,allList))).collect(Collectors.toList());
   }

给出一个结果集,构建树形结果集:

/**
    * 获取树形结构
    * @param mapList
    * @return treeList 树形结果集
    */
   public static List<Map<String, Object>> getJava8ResultTree(List<Map<String, Object>> mapList){
       if (CollectionUtils.isEmpty(mapList)){
           return Lists.newArrayList();
       }
       //filter过滤出所有的一级节点
       return mapList.stream().filter(m -> Objects.equals(m.get("parentId"), null) || Objects.equals(m.get("parentId"), ""))
               .peek(m -> m.put("children", sortJava8Map(getJava8Children(m, mapList)))).collect(Collectors.toList());
   }

获取树形结构:

//转化为Map集合
List<Map<String, Object>> mapList = BeanMapUtils.listBeanToListMap(nodePOs);
//获取树形结构
List<Map<String, Object>> java8ResultTree = getJava8ResultTree(mapList);
//打印输出
System.out.println(JSON.toJSONString(java8ResultTree));

打印结果:

[{"orderNo":"_0001","children":[{"orderNo":"_0002","children":[],"name":"二级节点1.1","id":"2","parentId":"1"},{"orderNo":"_0003","children":[],"name":"二级节点1.2","id":"3","parentId":"1"}],"name":"一级节点1","id":"1"},{"orderNo":"_0004","children":[{"orderNo":"_0005","children":[],"name":"二级节点2.1","id":"5","parentId":"4"},{"orderNo":"_0006","children":[{"orderNo":"_0007","children":[],"name":" * 节点2.2.1","id":"7","parentId":"6"}],"name":"二级节点2.2","id":"6","parentId":"4"}],"name":"一级节点2","id":"4"},{"orderNo":"_0008","children":[{"orderNo":"_0009","children":[{"orderNo":"_0010","children":[{"orderNo":"_0011","children":[{"orderNo":"_0012","children":[],"name":"五级节点3.1.1.1.1","id":"12","parentId":"11"}],"name":"四级节点3.1.1.1","id":"11","parentId":"10"}],"name":" * 节点3.1.1","id":"10","parentId":"9"}],"name":"二级节点3.1","id":"9","parentId":"8"}],"name":"一级节点3","id":"8"}]

树形结构搞定!两种实现方式对比一下,你就说Java8的方式哇塞不哇塞!!!

来源:https://blog.csdn.net/qq_52596258/article/details/127471217

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