使用OpenGL绘制Bezier曲线

本文实例为大家分享了OpenGL绘制Bezier曲线的具体代码，供大家参考，具体内容如下

最近在看Francis S Hill ,Jr 和 Stephen M Kelley合著的《计算机图形学》(OpenGL版)(第三版)书中有绘制三个控制点的Bezier曲线的代码。自己重新敲了一遍代码。发现了其中的一点小错误，修正过来了。并做了一点小小的改动。

源码见下

#include <windows.h>
#include <math.h>
#include <gl/GL.h>
#include <gl/glut.h>
int SCREEN_HEIGHT = 480;
int NUMPOINTS = 0;
class Point
{
public:
float x, y;
void setxy(float x2, float y2)
{
x = x2;
y = y2;
}
Point operator&(const Point & rPoint)
{
x = rPoint.x;
y = rPoint.y;
return * this;
}
};
Point abc[3];
void myInit()
{
glClearColor(0.0,0.0,0.0,0.0);
glColor3f(1.0f, 0.0, 0.0);
glPointSize(4.0);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluOrtho2D(0.0, 640, 0.0, 480.0);
}
void drawDot(Point pt)
{
glBegin(GL_POINTS);
glVertex2f(pt.x, pt.y);
glEnd();
glFlush();
}
void drawLine(Point p1, Point p2)
{
glBegin(GL_LINES);
glVertex2f(p1.x, p1.y);
glVertex2f(p2.x, p2.y);
glEnd();
glFlush();
}
//三个控制点的贝塞尔曲线
Point drawBezier(Point A, Point B, Point C, double t)
{
Point P;
P.x = pow((1-t), 2) * A.x + 2*t*(1-t)*B.x + pow(t, 2)*C.x;
P.y = pow((1-t), 2) * A.y + 2*t*(1-t)*B.y + pow(t, 2)*C.y;
return P;
}
void myMouse(int button, int state, int x, int y)
{
if(button == GLUT_LEFT_BUTTON && state == GLUT_DOWN)
{
abc[NUMPOINTS].setxy((float)x, (float)(SCREEN_HEIGHT - y));
NUMPOINTS++;
if (NUMPOINTS == 3)
{
 glColor3f(1.0, 0.0, 1.0);

drawDot(abc[0]);
 drawDot(abc[1]);
 drawDot(abc[2]);
 glColor3f(1.0, 1.0, 0.0);
 drawLine(abc[0], abc[1]);
 drawLine(abc[1], abc[2]);
 glColor3f(0.0, 1.0, 1.0);
 Point POld = abc[0];
 for (double t = 0.0; t<=1.0;t+=0.1)
 {
 Point P = drawBezier(abc[0], abc[1], abc[2], t);
 drawLine(POld, P);
 POld = P;
 }
 glColor3f(1.0, 0.0, 0.0);
 NUMPOINTS = 0;
}
}
}
void myDisplay()
{
glClear(GL_COLOR_BUFFER_BIT);
glFlush();
}
int main(int argc, char * agrv[])
{
glutInit(&argc, agrv);
glutInitDisplayMode(GLUT_SINGLE | GLUT_RGB);
glutInitWindowSize(640, 480);
glutInitWindowPosition(100, 150);
glutCreateWindow("Bezier Curve");
glutMouseFunc(myMouse);
glutDisplayFunc(myDisplay);
myInit();
glutMainLoop();
return 0;
}

来源：https://blog.csdn.net/dreamcs/article/details/5907734