java实现快速打字游戏

本文实例为大家分享了java实现打字游戏的具体代码，供大家参考，具体内容如下

import java.util.Random;
import java.util.Scanner;

public class Game {

public Game(Player player) {

}
public Game() {

}

public String printStr(Player player) {
StringBuffer a=new StringBuffer();
for(int i=0;i<LevelParam.levels[player.getLevelNo()-1].getStrLength();i++) {
int num=(int)(Math.random()*(7));
switch(num) {
case 1:
a.append(">");
break;
case 2:
a.append("<");
break;
case 3:
a.append("+");
break;
case 4:
a.append("-");
break;
case 5:
a.append("*");
break;
case 6:
a.append("/");
break;
case 0:
a.append("=");
break;
}
}
String str=a.toString();
System.out.println(str);
return str;
}

public void printResult(Player player) {
String num1=this.printStr(player);
Scanner input=new Scanner(System.in);
player.setStartTime();
String num2=input.next();
long currentTime=System.currentTimeMillis();
player.setElapsedTime(currentTime,player.getStartTime());
if (num1.equals(num2)) {
if ((currentTime-player.getStartTime())/1000>LevelParam.levels[player.getLevelNo()-1].getTimeLimit()) {
System.out.println("你输入太慢了，输入超时，退出。");
System.exit(1);
} else {
player.setCurScore(player);
System.out.println("输入正确，您的级别"+player.getLevelNo()+",您的积分"+player.getCurScore()+",已用时"+player.getElapsedTime()+"秒。");
}
}else{
System.out.println("输入错误，退出！");
System.exit(1);
}
}
}

public class Level {
private int levelNo;//各级别编号
private int strLength;//各级别一次输出字符串的长度
private int strTimes;//各级别输出字符串的次数
private int timeLimit;//各级别闯关的时间限制
private int perScore;//各级别正确输入一次的得分

public int getLevelNo() {
return levelNo;
}
public int getStrLength() {
return strLength;
}
public int getStrTimes() {
return strTimes;
}
public int getTimeLimit() {
return timeLimit;
}
public int getPerScore() {
return perScore;
}

public Level(int levelNo,int strLength,int strTimes,int timeLimit,int perScore) {
this.levelNo=levelNo;
this.strLength=strLength;
this.strTimes=strTimes;
this.timeLimit=timeLimit;
this.perScore=perScore;
}
}

public class LevelParam {
public static final Level levels[]=new Level[6];
static{
levels[0]=new Level(1,2,10,30,1);//编号、字符串长度、字符串次数、关卡时间、正确得分
levels[1]=new Level(2,3,9,26,2);
levels[2]=new Level(3,4,8,22,5);
levels[3]=new Level(4,5,7,18,8);
levels[4]=new Level(5,6,6,15,10);
levels[5]=new Level(6,7,5,12,15);
}
}

import java.util.Scanner;

public class Player {
private int levelNo=1;//玩家当前级别
private int curScore;//当前级别积分
private long startTime;//当前级别开始时间
private long elapsedTime;//当前级别已用时间

public int getLevelNo() {
return levelNo;
}
public void setLevelNo() {
this.levelNo++;
}
public int getCurScore() {
return curScore;
}
public void setCurScore(Player player) {
this.curScore = curScore+LevelParam.levels[player.getLevelNo()-1].getPerScore();;
}
public void setCurScore(int a) {
this.curScore=a;
}
public long getStartTime() {
return startTime;
}
public void setStartTime() {
this.startTime =System.currentTimeMillis();;
}
public long getElapsedTime() {
return elapsedTime;
}
public void setElapsedTime(long a,long b) {
this.elapsedTime=(a-b)/1000+elapsedTime;
}
public void setElapsedTime(int a) {
this.elapsedTime=a;
}

public void play(Player player) {
Game one=new Game();
for(int j=0;j<6;j++) {
for(int i=0;i<LevelParam.levels[player.getLevelNo()-1].getStrTimes();i++) {
one.printResult(player);
}
player.setLevelNo();
player.setCurScore(0);
player.setElapsedTime(0);
}
}
}

public class Test {
public static void main(String[] args) {
Player p=new Player();
p.play(p);
}
}

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来源：https://blog.csdn.net/CYH_progress/article/details/107081036