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C#文件操作的简单实例

　　发布时间：2021-12-14 16:50:40　

标签：C#,文件操作

文件的读取


 FileStream fs = new FileStream(@"D:\12.txt", FileMode.Open);
            byte[] buffer = new byte[1024 * 1024];
            fs.Read(buffer, 0, buffer.Length);
            string content = Encoding.Default.GetString(buffer);
            textBox1.Text = content;
            fs.Dispose();


文件的保存


 SaveFileDialog sfd = new SaveFileDialog();
            DialogResult rst = sfd.ShowDialog();
            if(rst==System.Windows.Forms.DialogResult.OK)
            {
                FileStream fs = new FileStream(sfd.FileName,FileMode.Create);
                string content = textBox1.Text;
                byte[] buffer = ASCIIEncoding.UTF8.GetBytes(content);
                fs.Write(buffer,0,buffer.Length);
                fs.Dispose();


文件的复制


FileStream streamread = new FileStream(@"D:\123.wmv",FileMode.Open);
            FileStream streamwrite = new FileStream(@"F:\1212.wmv",FileMode.Create);
            byte[]buffer=new byte[1024*1024*3];
            int Length;
            do
            {
                Length = streamread.Read(buffer,0, buffer.Length);
                streamwrite.Write(buffer,0, Length);
            }
            while (Length == buffer.Length);
            streamread.Dispose();
            streamwrite.Dispose();
            MessageBox.Show("Copy Success");
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