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python pycurl验证basic和digest认证的方法

作者:lilongsy  发布时间:2022-12-17 23:01:15 

标签:python,digest,basic

简介

pycurl类似于Python的urllib,但是pycurl是对libcurl的封装,速度更快。

本文使用的是pycurl 7.43.0.1版本。

Apache下配置Basic认证

生成basic密码文件


htpasswd -bc passwd.basic test 123456

开启mod_auth_basic


LoadModule auth_basic_module modules/mod_auth_basic.so

配置到具体目录


<Directory "D:/test/basic">
 AuthName "Basic Auth Dir"
 AuthType Basic
 AuthUserFile conf/passwd.basic
 require valid-user
</Directory>

重启Apache

Apache下配置Digest认证

生成Digest密码文件


htdigest -c passwd.digest "Digest Encrypt" test

开启mod_auth_digest


LoadModule auth_digest_module modules/mod_auth_digest.so

配置到具体目录


<Directory "D:/test/digest">
 AuthType Digest
 AuthName "Digest Encrypt" # 要与密码的域一致
 AuthDigestProvider file
 AuthUserFile conf/passwd.digest
 require valid-user
</Directory>

重启Apache

验证Basic认证


# -*- coding: utf-8 -*-
import pycurl
try:
 from io import BytesIO
except ImportError:
 from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/basic/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_BASIC)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()

验证Digest认证


# -*- coding: utf-8 -*-
import pycurl
try:
 from io import BytesIO
except ImportError:
 from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/digest/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_DIGEST)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()

来源:https://blog.csdn.net/lilongsy/article/details/79086569

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